ashleyo161
ashleyo161
15-04-2018
Mathematics
contestada
How many zeros are there in -5x(x-3)(x^2-16)
Respuesta :
claudettoterohil
claudettoterohil
15-04-2018
Simplify:
(( - 5x)(x - 3))(x^2 - 16)
= (( -5x)(x - 3))(x^2 + - 16)
= (( -5x)(x - 3))(x^2) + (( -5x)(x - 3))( - 16)
= - 5x^4 + 15x^3 + 80^2 - 240x
= - 5x^4 + 15x^3 + 80x^2 - 240x
There are 4 Zeros...
Hope it helps!!!
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