(3-5i)(2+9i)+(7+2i)(7-2i)

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01-02-2016
Mathematics

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(3-5i)(2+9i)+(7+2i)(7-2i)

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Benjamin16 Benjamin16 · Answer 1 · 2016-02-01T12:44:16+01:00

Benjamin16 Benjamin16

01-02-2016

[tex]i^{2} = -1[/tex]

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[tex](3-5i)(2+9i)+(7+2i)(7-2i) = \\ \\ = 6 + 27i - 10i - 45i^{2} + 49 - 14i + 14i - 4i^{2} = \\ \\ =55 + 17i + 45 + 4 = \boxed{104 + 17i} [/tex]

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