A cheetah has an acceleration that has x and y components of ax = 5.3 m/s2 and ay = 3.8 m/s2. the cheetah's mass is 61 kg. find the net force acting on the cheetah.
cheetah has an acceleration that has x and y components of ax = 5.3 m/s2 and ay = 3.8 m/s2. the cheetah's mass is 61 kg. Now, we will calculate the force in both the directions and then find the resultant force.
The force in the x direction is, F1 = 61kg*5.3m/s2 = 323.3 N The force in the y direction is F2 = 61kg*3.8m/s2 = 231.8 N
Therefore the total force written as a vector is: (Taking positive x direction as i direction and the negative direction as j direction) F= (323.3i + 231.8j)N
