Respuesta :

apologiabiology
make denomenators the same

times left denomenator by (x+3)/(x+3) and right one by (x-9)/(x-9)

[tex] \frac{3(x+3)}{(x-9)(x+3)}+ \frac{5(x-9)}{(x-9)(x+3)}[/tex]=
[tex]\frac{3(x+3)+5(x-9)}{(x-9)(x+3)}[/tex]=
[tex]\frac{3x+9+5x-45}{(x-9)(x+3)}[/tex]=
[tex]\frac{8x-36}{(x-9)(x+3)}[/tex]

if expandded we get
[tex]\frac{8x-36}{x^2-6x-27}[/tex]

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