Respuesta :

baseballboyg
The perimeter of a rectangle is given as:

[tex]P_{rect}=2w+2l[/tex]

We know that

[tex]l=\frac{1}{3}*w{/tex]

as the length is one-third of the width.  Now we can plug numbers in:

[tex]72=2w+\frac{2}{3}w = 72=\frac{8}{3}w[/tex]

Now we can solve for width:

[tex]w=27[/tex]

And if the length is one-third the width, we know that 

[tex]27*\frac{1}{3} = 9

w=9[/tex]

And [tex]A_{rect}=lw[/tex]

So now we plug in numbers:

[tex]A_{rect}=27*9 = 243[/tex]

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