Respuesta :
The magnitude of the resulting forces applied to the nails if they are located at A and B is 64.44 N, at B and C is 120.83 N and at A and C is 56.86 N.
We know that,
C = F d
where,
C = Couple
F = Magnitude of resulting forces
d = Distance between two points
Given that,
C = 29 N m
[tex]d_{AB}[/tex] = 450 mm = 0.45 m
[tex]d_{BC}[/tex] = 240 mm = 0.24 m
F = C / d
The magnitude of the resulting forces applied to the nails if they are located at A and B is
F = 29 / [tex]d_{AB}[/tex] = 29 / 0.45
F = 64.44 N
The magnitude of the resulting forces applied to the nails if they are located at B and C is
F = 29 / [tex]d_{BC}[/tex] = 29 / 0.24
F = 120.83 N
The magnitude of the resulting forces applied to the nails if they are located at A and C is
F = 29 / [tex]d_{AC}[/tex]
[tex]d_{BC}[/tex] = √ ( [tex]d_{AB}[/tex] )² + ( [tex]d_{BC}[/tex] )²
[tex]d_{BC}[/tex] = √ ( 0.45² + 0.24² )
[tex]d_{BC}[/tex] = 0.51 m
F = 29 / 0.51
F = 56.86 N
A Couple is two parallel forces of equal magnitude acting in opposite direction.
Therefore, the magnitude of the resulting forces applied to the nails if they are located at
- A and B is 64.44 N
- B and C is 120.83 N
- A and C is 56.86 N
To know more about couples
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