Respuesta :

Explanation:

Soln:-

Given:-

Volume(v)=5.0cm^3

mass(m)=13.5 gm

density (d)=?

We know that,

d=v

=(13.5÷5)g/cm^3

=2.7g/cm^3

Hence, the required density of aluminum is 2.7g/cm^3.