Respuesta :

LammettHash
The slope of the tangent line to [tex]y=3\sin^2\dfrac x2[/tex] is

[tex]y'(x)=3\sin\dfrac x2\cos\dfrac x2=\dfrac32\sin x\implies y'(\pi)=0[/tex]

which means the tangent line at this point is horizontal.

Because the tangent line passes through

[tex]y(\pi)=3\sin^2\dfrac\pi2=3[/tex]

the tangent line has equation [tex]y=3[/tex].

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