Respuesta :
(a) The number of molecules contained by the balloon at the given condition is 6,438.97 moles.
(b) The mass of air in the balloon is 186.73 kg.
The given parameters;
- volume of the balloon, V = 1500 m³
- temperature, T = 10⁰C = 273 + 10 = 283 K
- pressure, = P = 10.1 kPa = 10,100 Pa
The number of molecules contained by the balloon at the given condition is calculated as follows;
[tex]PV = nRT[/tex]
where;
- R is ideal gas constant = 8.314 J/mol.K
- n is the number of moles air in the balloon;
[tex]n = \frac{PV}{RT} \\\\n = \frac{10,100 \times 1500}{8.314 \times 283} \\\\n = 6,438.97 \ moles[/tex]
The mass of air in the balloon is calculated as;
[tex]n = \frac{m}{M} \\\\m = nM\\\\m = 6,438.97\ moles \ \times \ 29 \ g/mol\\\\m = 186.73 \ kg[/tex]
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