cmdqservices
cmdqservices
14-10-2021
Mathematics
contestada
factor by grouping jk^2+3jk+9k+27
Respuesta :
hf0028321
hf0028321
16-10-2021
Answer:
(jk+9)(k+3)
Step-by-step explanation:
jk(k+3)+9(k+3)=(jk+9)(k+3)
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