Answer:
40.0 L
Explanation:
The formula to find the new pressure: [tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}[/tex]
P₁ = 15.0 L
V₁ = 2 atm
T₁ = 300 K (Convert Celsius to Kelvin by adding 273)
P₂ = 1
V₂ = ?
T₂ = 400 K
[tex]\frac{(2)(15)}{300} = \frac{P_2(1)}{400}[/tex]
[tex]\frac{30}{300} = \frac{P_2}{400}[/tex]
[tex]\frac{1}{10} = \frac{P_2}{400}[/tex]
Multiply both sides by 400 to isolate the P₂
[tex]\frac{400}{10} = P_2[/tex]
[tex]P_2 = 40[/tex]
