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A simple machine has an IMA of 7. If the effort force of 5N is applied over a distance of 4m, what is the ideal resistance force, and how far does the load travel?a) Fr = 0.71 N and dr = 0.57 m.b) Fr = 0.71 N and dr = 28 m.c) Fr = 35 N and dr = 0.57 m. d) Fr = 35 N and dr = 28 m.

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Answer:

Option C

Explanation:

From the question we are told that:

[tex]IMA=7[/tex]

Effort force [tex]F_e=5N[/tex]

Effort distance [tex]d_e=4m[/tex]

Generally the equation for IMA is mathematically given by

In Terms of Distance

[tex]IMA=\frac{d_e}{d_x}[/tex]

[tex]7=\frac{4}{d_x}[/tex]

[tex]d_x=0.57m[/tex]

In Terms of Force

[tex]IMA=\frac{F_x}{F_e}[/tex]

[tex]7=\frac{F_x}{5}[/tex]

[tex]F_x=35N[/tex]

Therefore

[tex]F_x=35N[/tex] and [tex]d_x=0.57m[/tex]

Option C

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