Answer:
x = -3, 0, 2
Step-by-step explanation:
=> x³ + x² - 6x = 0
=> x(x² + x - 6) = 0
=> x² + x - 6 = 0 or x = 0
=> x² + 3x - 2x - 6 = 0 or x = 0
=> x(x + 3) - 2(x + 3) = 0 or x = 0
=> (x + 3)(x - 2) = 0 or x = 0
=> x = - 3 or x = 2 or x = 0
