Answer:
F = - 1872 N
Step-by-step explanation:
Given that,
Charge 1, [tex]q_1=-2\times 10^{-4}\ C[/tex]
Charge 2, [tex]q_2=6.5\times 10^{-5}\ C[/tex]
The distance between charges, r = 0.25 m
We need to find the force between the two charges. The formula for force between two charges is given by :
[tex]F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times -2\times 10^{-4}\times 6.5\times 10^{-5}}{(0.25)^2}\\\\F=-1872\ N[/tex]
So, the force between the charges is equal to 1872 N.
