Answer:
7.12 × 10⁻³ M/s
Explanation:
Step 1: Write the balanced reaction
2 SO₂ + O₂ ⇒ 2 SO₃
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of O₂ to SO₃ is 1:2.
Step 3: Calculate the rate of formation of SO₃
The rate of loss of O₂ is 3.56 × 10⁻³ mol O₂/L.s. The rate of formation of SO₃ is:
3.56 × 10⁻³ mol O₂/L.s. × 2 mol SO₃/1 mol O₂ = 7.12 × 10⁻³ mol SO₃/L.s
