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The 15th term of an arithmetic sequence is 110 and the 19rd term of the sequence is 134.
a) Find the common difference.
b) Find the first term.
c) What is the 25th term?

Respuesta :

Step-by-step explanation:

a) Common Difference = ?

15th term = 110

19th = 134

134 - 110

= 24/4

= 6

Common Difference = 6

b) First term = ?

110 = x+ (14) 6

x = 110 - 84

x = 26

First term = 26

c) 25th term = ?

= x 25 = 26+ (25)6

= x 25 = 176

25th term = 176.

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