Use Coulomb's Law to calculate the energy of a copper ion and an oxide ion at their equilibrium ion-pair separation distance.
Cu^2+ radius(pm)= 77 O^-2 radius (pm)=140 answer in aJ

Respuesta :

E= (231 aj/pm) (-2)(2)/77+140 Pm

E= 231 aj (-4)/217

E= -868 aj/ 217

E= -4aj