Answer:
[tex]P_2=2.60atm[/tex]
Explanation:
Hello!
In this case, since the temperature and pressure are related via a directly proportional relationship, via the Gay-Lussac's law we can write:
[tex]\frac{P_1}{T_1} =\frac{P_2}{T_2}[/tex]
Thus, since the initial temperature in kelvins is 294.15 K and the final temperature in kelvins is 364.15 K, we can compute the final pressure as shown below:
[tex]P_2=\frac{P_1T_2}{T_1} =\frac{2.10atm*364.15K}{294.15K}\\\\P_2=2.60atm[/tex]
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