Answer:
x = 95 [m]
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]v_{f} =v_{o} +a*t[/tex]
where:
Vf = final velocity = 19 [m/s]
Vo = initial velocity = 0 (starts from the rest)
a = acceleration [m/s²]
t = time = 10 [s]
Now we can find the acceleration
19 = 0 *a*(10)
a = 1.9 [m/s]
With the second equation we can find the distance:
[tex]v_{f} ^{2} =v_{o} ^{2} +(2*a*x)[/tex]
where:
x = distance [m]
(19)² = (0)² + (2*1.9*x)
3.8*x = 361
x = 95 [m]
