Answer:
B.9, 4, β1, β6
Step-by-step explanation:
A sequence can be generated by using an=anβ1+9, where a1=β5 and n is a whole number greater than 1. What are the first four terms in the sequence?
A.β5, 4, 13, 22
B.9, 4, β1, β6
C.β5, β45, β405, β3645
D. 9, β45, 225, β1125
From the above question,
A sequence can be generated by using an=a(nβ1)+9, where a1=β5
The formula = an = a1 + (n - 1)d
a1 = First term
d = common difference = 9
We are to find the first 5 terms
First term = a1 =
an=anβ1+9, where a1=β5
The formula =
a1 = -5 (1 - 1) + 9
= -5(0) 9
= -9
Second term = a2 =
an=anβ1+9, where a1=β5
The formula = an = a1 (n - 1) + d
a2 = -5(2 - 1) + 9
= -5(1)+ 9
= -5 + 9
= 4
Third term = a3 =
an=anβ1+9, where a1=β5
The formula = an = a1(n - 1) + d
a3 = -5(3 - 1)9
= -5(2) + 9
= -10+ 9
= -1
Fourth term = a2 =
an=anβ1+9, where a1=β5
The formula = an = a1(n - 1) + d
a4 = -5(4 - 1)9
= -5(3) +9
= -15 +9
= -6