we know that
The volume of a cylinder is given by the formula
[tex]V=3.14 r^{2} h[/tex]
where
r is the radius of the cylinder
h is the height of the cylinder
in this problem
[tex]r=x+8\\h=2x+3[/tex]
Substitute the values in the formula above
[tex]V=3.14*(x+8)^{2}*(2x+3)[/tex]
[tex]V=3.14*(x^{2}+16x+64)*(2x+3) \\ V=3.14 *(2x^{3} +3x^{2} +32x^{2} +48x+128x+192)\\ V=3.14*(2x^{3} +35x^{2} +176x+192)[/tex]
therefore
the answer is
The volume of the can is equal to
[tex]V=3.14 *(2x^{3} +35x^{2} +176x+192)\ units ^{3}[/tex]
