Answer:
The period of oscillation is 2.01 s
Explanation:
Given;
mass of the attached ball, m = 500 g
length of the string, L = 1 m
The period of oscillation of a conical pendulum is given as;
[tex]T = 2 \pi\sqrt{\frac{l \ cos \theta}{g}}[/tex]
θ = 0, since the mass is allowed to moved in horizontal direction
[tex]T = 2 \pi\sqrt{\frac{l }{g}} \\\\T = 2 \pi\sqrt{\frac{1 }{9.8}} \\\\T = 2 \pi (0.31944)\\\\T = 2.01 \ s[/tex]
Therefore, the period of oscillation is 2.01 s
