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If the pressure exerted by a gas at 0.00 °C in a volume of 0.0010 L of 5.00 atm, how many moles of gas are present?

Respuesta :

Answer:

2.23 x 10^-4 mol

Explanation:

0°C =273 K

PV= nRT

n= PV/RT

n= (5.00 atm * 0.0010 L)/ (0.0821 * 273 K)

n= 2.23 x 10^-4

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