nale2561 nale2561

13-05-2020
Chemistry

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How many mL of 1.00M HCl are needed to neutralize 400mL of 0.200M NaOH?

Respuesta :

valeherrera333 valeherrera333

14-05-2020

Answer:

80 mL

Explanation:

M= mol solute/ L solution

mol solute= M * L solution

mol solute = (0.200 M * 0.4 L)

mol solute = 0.08 mol NaOH= mol OH

We need the same amount of H mol to neutralize

L solution= mol solute/M

L solution= 0.08 mol HCl/ 1.00M

L solution= 0.08 L= 80 mL

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