Answer:
3241.35J
Explanation:
No. Of rods = 5
Mass = 2.89kg
Length (L) = 0.827m
W = 507rpm
Kinetic energy of rotation = ½I*ω²
For each rod, the moment of inertia (I) = ML² / 3
I = ML² / 3
I = [2.89*(0.827)²] / 3
I = 1.367 / 3 = 0.46kgm²
ω = 507 rev/min. Convert rev/min to rev/sec.
507 * 2Πrads/60s = 53.09rad/s
ω = 53.09rad/s
k.e = ½ I * ω²
K.E = ½ * 0.46 * (53.09)²
K.E = 648.27.
But there five (5) rods, so kinetic energy is equal to
K.E = 5 * 648.27 = 3241.35J
