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Jessie is working with a 100% stock concentration of Clorox. She decides to add 150 µL of bacteria to a tube containing 2 mL of nutrient broth and then adds 200µL of the Clorox stock to the tube as well. What is the unknown concentration of the tube?

Respuesta :

Answer:

8.51%

Explanation:

C1V1 = C2V2

Here,

C1 = Starting concentration = 100%

V1 = Starting volume = 200μL

C2 = Final concentration = to find out

V2 = Final volume = 2000 + 150 + 200 = 2350μL

100 * 200 = C2 * 2350

C2 = 100 * 200 / 2350

= 20000 / 2350

= 8.51%

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