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What are two consecutive odd integers, such that six times the larger minus two times the smaller is 152?

Respuesta :

Answer:

35 & 37

Step-by-step explanation:

Call the first integer n and the second n-2 (they're odd so every OTHER number is consecutive)

6 (n+2) -2n=152

6n + 12-2n =152

4n= 152-12

4n=140

4n/4= 140/4

n=37

So then to get your second integer plug it in for n-2

37-2=

35

(n-2)=35

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