Answer:
(A) 0.001 m
(B) 0.75 m/s
(C) [tex]5.7 x 10^{2} m/s^{2}[/tex]
Explanation:
distance (d) = 2 mm
frequency (f) = 120 Hz
(A) amplitude (A) = half the distance moved by the blade
amplitude = 2 / 2 = 1 mm = 0.001 m
(B) maximum blade speed (v) = ωA = 2πfA
v = 2 x 3.14 x 120 x 0.001 = 0.75 m/s
(c) maximum blade acceleration (a) = [tex]w^{2}A[/tex]
a = [tex](2 x 3.14 x 120)^{2}x0.001[/tex] = [tex]5.7 x 10^{2} m/s^{2}[/tex]
