Answer:
A) Force = 0.69 N
B) Acceleration = 0.34 m/s^2
Explanation:
The electric force is given by the expression:
[tex]F_e= K *\frac{q_1*q_2}{r^2}[/tex]
K is the Coulomb constant equal to 9*10^9 N*m^2/C^2, q1 and 12 is the charge of the particles, and r is the distance:
[tex]F_e = 9*10^9 Nm^2/C^2 * \frac{(9.6*10^{-6}C)^2}{(1.1m)^2} = 0.69 N[/tex]
Part B.
For the acceleration, you need Newton's second Law:
F = m*a
Then,
[tex]a = \frac{F}{m} = \frac{0.69 N}{2 kg} = 0.34 m/s^2[/tex]
