Answer:
By time unit, the heat loss is 2571.43 W, approximately.
Explanation:
In this case, heat loss by conduction is given by
[tex]\frac{Q}{t}=\frac{kA\left(T_2-T_1\right)}{d}[/tex]
where Q stands for heat, t for time, k for the slab's conductivity, A for the area and T for temperature. Assuming a thermal conductivity of 0.16 W/m°C, we have
[tex]\frac{Q}{t}=\frac{0.16*10*15\left(21-6\right)}{0.14}\approx 2571.43[/tex]. Recall the units are Watts.
