Answer: Range(max) = e(max)-a(min) = 19-1 =18
Step-by-step explanation:
The Range is expressed as e-a.
Given that d-b=3 or d=b+3 and Average = 6 thus a+b+c+d+e=30
To maximize range, we need to minimize a and maximize e. Minimum a is 1, so we choose that.
Since sum is fixed, we should choose minimum possible values for b,c,d to maximize e.
b>a, minimum choice is 2
c>b, minimum choice is 3
d=b+3 so d=5
So e(max) = 30 - a(min) -b(min) -c(min) - d(min) = 30-1-2-3-5 = 19
Range(max) = e(max)-a(min) = 19-1 =18
