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In triangle ΔABC, ∠C is a right angle and segment CD is the height to segment AB . Find the angles in ΔCBD and ΔCAD if m∠A = 20°


m∠CDB =

m∠CBD =

m∠BCD =

m∠CDA =

m∠ CAD=

m∠ACD =

In triangle ΔABC C is a right angle and segment CD is the height to segment AB Find the angles in ΔCBD and ΔCAD if mA 20mCDB mCBD mBCD mCDA m CAD mACD class=