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Write the equation of a line that is perpendicular to the given line and that passes through the given point. y=2/3x+9 m (–6, 5)

Respuesta :

RizkyAmalia

Question :

Write the equation of a line that is perpendicular to the given line and that passes through the given point. y=2/3x+9 m (–6, 5)

Answer :

y = -3/2x - 4

Explanation :

y = mx + c

*m = gradien

•>looking for gradients

y=2/3x+9

m1 = 2/3

m2 = -3/2

•>line equation (-6,5)

y - y1 = m(x - x1)

y - 5 = -3/2(x - (-6))

y - 5 = -3/2(x + 6)

y - 5 = -3/2 - 9

y = -3/2x - 9 + 5

y = -3/2x - 4