Gigiii
Gigiii
13-04-2016
Mathematics
contestada
factor this radical expression. 50a^2-10ab/20a^3b^3
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DeannaJ
DeannaJ
13-04-2016
1)split into two fractions
[tex] \frac{50a^{2} }{20a ^{3} b ^{3} } [/tex] - [tex] \frac{10ab }{20a ^{3} b ^{3} } [/tex]
2) cancel what you can on both sides
[tex] \frac{5}{2ab ^{3} } [/tex] - [tex] \frac{1}{2a ^{2}b ^{2} } [/tex]
3) Make the denominators the same by cross multiplying and then put together as 1 fraction again
[tex] \frac{5a-b}{2a ^{2}b ^{2} } [/tex]
Answer Link
apologiabiology
apologiabiology
13-04-2016
remembe
(ax)/(bx)=(a/b)(x/x)=(a/b)1
find ones aka common factors and use distributive
top
50a^2-10ab
common facotrs is 10a
undistribute (ab+ac=a(b+c))
10a(5a-b)
bottom
20a^3b^3
see if 10a is also a common factor and undistribute that to cancel and make ones
10a(2a^2b^2)
now we have
[tex] \frac{10a(5a-b)}{10a(2a^{2}b^{3}} [/tex]=[tex] \frac{10a}{10a} [/tex] [tex] \frac{5a-b}{2a^{2}b^{3}} [/tex]
Answer Link
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