For this case we have the following expression:
[tex]8x <-32[/tex]
The x must be cleared, for which the 8 (which is multiplying to the x) is passed, to the other side of the inequality, dividing to -32. So, we have left:
[tex]x <-\frac{32}{8}[/tex]
Dividing we have:
[tex]x <-4[/tex]
So, the solution is [tex]x <-4[/tex]
Answer:
Option A