kxk07
contestada

What is the equation of the line that passes through (-3, -1) and has a slope of 2/5 ? Put your answer in slope-intercept form.

y = 2/5x + 1/5
y = 2/5x - 1/5
y = -2/5x - 1/5

Respuesta :

[tex] \bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{-1})\qquad \qquad \qquad
slope = m\implies \cfrac{2}{5}
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-1)=\cfrac{2}{5}[x-(-3)]
\\\\\\
y+1=\cfrac{2}{5}(x+3)\implies y+1=\cfrac{2}{5}x+\cfrac{6}{5}
\\\\\\
y=\cfrac{2}{5}x+\cfrac{6}{5}-1\implies y=\cfrac{2}{5}x+\cfrac{1}{5} [/tex]