Suppose a laboratory has a 31 g sample of polonium-210. The half-life of polonium-210 is about 138 days. a. How many half-lives of polonium-210 occur in 966 days? b. How much polonium is in the sample 966 days later?
Po 210 T½ = 138 days Half-Lives = 966 / 138 = 7 half lives For EACH half life, one half of the original remains. So, for 7 half lives, we would have 1 / (2^7) remaining. 2^7 = 128 1 / 128 =
0.0078125
So, after 966 days we would have: 31 *
0.0078125
=
0.2421875 grams remaining Source1728.com/halflife.htm
